Not able to establish friend relation between RTC & Jira
I am using Rational OSLC adapter(task top sync adapter v_4.18.1) to sync RTC v_6.0.5 and Jira v_8.1.0. I am trying to establish friend relationship between RTC-Jira but when I add rootservices URL as http://hostname:port/oslc/rootservices in RTC, it is throwing an error as mentioned below:
An error occurred while requesting the root services document from server "http://hostname:8080/oslc/rootservices". Please check the URL and try again.ID CRJAZ1575E
Please suggest how can I configure Jira as a friend in RTC? any additional plugin is required for that?
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One answer
Ralph Schoon (63.3k●3●36●46)
| answered May 27 '19, 9:30 a.m.
FORUM ADMINISTRATOR / FORUM MODERATOR / JAZZ DEVELOPER If you paste the URL into a browser, what happens? Comments
Anjuri Kelaiya
commented May 28 '19, 8:09 a.m.
Thanks for your response Ralph.
It is providing response as mentioned below when I paste the URL into browser:
Oops, you've found a dead link.
Because the URI is invalid. Talk to your ADMINS and let them provide you with the public URI.
Anjuri Kelaiya
commented May 29 '19, 4:23 a.m.
I am accessing Jira application with that URI without any issue. the issue is only in finding root services. is there any other plugin required to add Jira as a friend in CLM applications?
Please let me know.
Ralph Schoon
commented May 29 '19, 5:41 a.m.
| edited May 29 '19, 5:50 a.m.
FORUM ADMINISTRATOR / FORUM MODERATOR / JAZZ DEVELOPER
If the URI "http://hostname:8080/oslc/rootservices" is for a Jira system, this is the wrong forum.
If the URI "http://hostname:8080/oslc/rootservices" is for a CLM/Jazz application, I can tell you that this is, with 99% likelihood, a wrong URI and you should ask the administrators of the CLM system for the correct context root of the application.
For any decently set up Jazz application it would look similar to https://<somehost><:someport>/<app>/rootservices , where <app> is one of jts, ccm, rm,... ports might be omitted.
Anjuri Kelaiya
commented May 30 '19, 5:33 a.m.
Many thanks for all your help Ralph. |
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