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question asked: Aug 07 '13, 2:19 p.m.
question was seen: 4,390 times
last updated: Aug 08 '13, 3:43 a.m.

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32-bit Installation Manager required for RRC v4.0.3??

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Anthony Kesterton (7.5k●9●180●136) | asked Aug 07 '13, 2:19 p.m.
JAZZ DEVELOPER
I am helping someone install RRC v4.0.3 on a Windows 2008 R3 server (it is a vmware machine, 64-bit, quad virtual core).  We are using Installation Manager and a downloaded repository from jazz.net. 

After we select RRC, JTS and the trial license keys - we get the warning that we should be using the 32-bit IM to install RRC v4.0.3.

Is this an error in IM - I have not noticed this message before when installing on other 64-bit machines.

anthony

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Simon Eickel (1.1k●7●54●57) | answered Aug 08 '13, 2:28 a.m.
Hi Anthony,

I've checked my situation - I have a Win 2008 R2 server - and there the Installation Manager is installed as a 32bit
application. Why is there no x64 installed?
I assume this explained with the historically fact. In our company we still have Windows XP (32bit) and Windows 7 (32bit). That's why we are using the IM in 32bit company-wide.

With this IM I was able to install all applications on the server as x64 architecture (JTS, RTC, RQM and RRC) and they are working fine.

When I check the Taskmanager during such an installation I don't find the java process to use more than 1xxk of memory ...
So my more general question is - what would be the benefit using an IM in x64 architecture?

Greetings,
Simon
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Anthony Kesterton commented Aug 08 '13, 3:43 a.m.
JAZZ DEVELOPER

Hi Simon

Many thanks for checking your setup. This has led me to believe that perhaps the person who downloaded IM picked a 64-bit version (if that is possible) by mistake.  I have something to check up on.

As far as the wider question goes of "why have a 64-bit version at all" - bear in mind that Installation Manager is a core IBM technology that is used in other IBM products.  They may have bigger memory requirements.  Also - if you run on a 64-bit system, you may not have the relevant 32-bit libraries available to execute the code.  This is all my impression, and may not be the correct reason :-)

anthony

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