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Unable to filter RRC REST result by using resourceURI

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Erwin Kunz
(946●8●70●86) Mar 27 '13, 5:52 a.m.
RRC 4.0.1

Based on WIKI page i should be able to filter by ID

Filter id(s) https://server:port/rm/publish/[artifact_format]?resourceURI=id1,id2,id3 Provides base resource information for a set of specified resources

when I try with:
https://server/rm/publish/resources?resourceID=_V5CWFYDcEeKbvZGEq7ALCg
the system returns me all resources...after 10 min

only filter working is
https://server/rm/publish/resources?projectURI=_ZRCINYC-EeKbvZGEq7ALC

and this one does return the same
https://server/rm/publish/resources?projectURI=_ZRCINYC-EeKbvZGEq7ALCg&resourceID=_V5CWFYDcEeKbvZGEq7ALCg

Anything I missed?
How can I get only e.g. Title from a list of URI

Thank you
erwin

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Erwin Kunz
Mar 27 '13, 6:35 a.m.

embarrassing :-)

Thank you Christian

additional question
why does https://server/rm/publish/resources?projectURI=_ZRCINYC-EeKbvZGEq7ALCg&resourceURI=_WG5y9YDcEeKbvZGEq7ALCg&fields=dataSource/artifact/(title)
not return only Title of this artifact

Christian Glockner
Mar 27 '13, 6:45 a.m.

Hello Erwin,


Looking at the Wiki there is a note in the row for "Filter by xpath" that reads:
The ?fields= argument is tolerated but does not alter the content returned from the REST API
I think that explains why you're seeing everything returned.

Erwin Kunz
Mar 27 '13, 9:49 a.m.

Oups.. again. Thank you

Edgar Ignacio Velazquez Mar
JAZZ DEVELOPER Mar 27 '13, 10:17 a.m.

 Hi Erwin,

 This filters are used when the schemas are added as REST, that is why Generic XML is suggested. It will not impact the output, but can be confusing

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Christian Glockner
(166●1●3) Mar 27 '13, 6:26 a.m.
Hello Erwin,

Is that just a typo in the first URL or did you really use "resourceID=" while it should be "resourceURI="?

-Christian
Technical Support Engineer
IBM Rational Client Support Europe 
Erwin Kunz selected this answer as the correct answer

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Question asked: Mar 27 '13, 5:52 a.m.

Question was seen: 4,882 times

Last updated: Mar 27 '13, 10:17 a.m.

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