how to checkout a specific version of a commit in a separate directory using lscm?

Ved Kpl (13●7) | asked Mar 10 '21, 10:22 a.m.
edited Mar 10 '21, 10:22 a.m.

Is there an easy way to checkout a a specific version of a commit (that has multiple files changed) into a separate directory?

Currently , I have to do "lscm list changes <commit_uuid> -j", then extract the state-uuid of each file from the output, and then for every file run "lscm get file -r https://localhost:9443/ccm <commit_uuid> <state_uuid> <out_file_path>" . This is pretty cumbersome. Is there a single command that can do the trick for me? Something like "git --work-tree=<workdir> --git-dir=<gitdir> checkout <commit_id>" in git.

Comments

Geoffrey Clemm commented Mar 10 '21, 10:29 a.m.

FORUM ADMINISTRATOR / FORUM MODERATOR / JAZZ DEVELOPER

Just for interest's sake, why do you want to do that?

Ved Kpl commented Mar 10 '21, 10:40 a.m.

I think this is a very basic usecase. I would like to move to a specific state of the code, when debugging or something like that.

Geoffrey Clemm commented Mar 10 '21, 1:14 p.m.

FORUM ADMINISTRATOR / FORUM MODERATOR / JAZZ DEVELOPER

It makes sense to have some components of a workspace loaded onto disk, but why a single change set?

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how to checkout a specific version of a commit in a separate directory using lscm?

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