Error(java.lang.IllegalStateException: More than 1 metadata storage manager registered for storage type com.ibm.team.filesystem.hfs) on loading a repository workspace programmatically!
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Hello ,
I am using plain java client api 6.0. I am creating a repository workspace using code : JoinOperations.createWorkspace(repo, selectedStream, this.readConfiguration.getRepo_Workspace_name(), this.readConfiguration.getRepoWorkspaceDesc(), null,monitor); Workspace is created correctly with all the components. And i am getting the ISandbox object by using below code : public ISandbox getSandboxForPath(ILocation sandboxPath) throws FileSystemException { ISharingManager sharingManager = SharingManager.getInstance(); // FileSystemCore.getSharingManager(); Collection<ISandbox> updatedSandBoxList = sharingManager .getRegisteredSandboxes(); ISandbox selSandbox = null; for (ISandbox sandboxTemp : updatedSandBoxList) { if (sandboxTemp.getRoot().toOSString() .equalsIgnoreCase(sandboxPath.toOSString())) { selSandbox = sandboxTemp; } } if (selSandbox == null) { selSandbox = getSandbox(sandboxPath, false); } sharingManager.register(selSandbox, false, null); return selSandbox; } public ISandbox getSandbox(ILocation copyFileAreaRoot, boolean registered) { if ((registered) && (!ICopyFileAreaManager.instance.copyFileAreaExists( copyFileAreaRoot, 0))) { return null; } return new Sandbox(copyFileAreaRoot); } and am using below code to load repo workspace : ILoadRule2 loadRule = ILoadRuleFactory.loadRuleFactory.getLoadRule( workspaceconn, lrFileReader, true, monitor); ILoadOperation loadoperator = loadRule.getLoadOp(this.sandbox, LoadDilemmaHandler.getDefault(), monitor); loadoperator.run(monitor); I get error message "java.lang.IllegalStateException: More than 1 metadata storage manager registered for storage type com.ibm.team.filesystem.hfs" at line :loadoperator.run(monitor); Could you please tell me how i it can be fixed ? |
Accepted answer
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Hello,
This was caused due to duplicate entries of com.ibm.filesystem.client jar file in eclipse workspace. Ralph Schoon selected this answer as the correct answer
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Your answer
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