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question asked: Apr 23, 2:38 a.m.
question was seen: 620 times
last updated: Apr 24, 4:29 p.m.

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Publishing Engine and DOORS - multivalued Enumerated types date extrtaction

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Janet Cook (23●1●10) | asked Apr 23, 2:38 a.m.

Using DOOR Snext 7.0.2 and Rational Publishing Engine.

I have no issues getting enumerated data out when there is only one value allowed. 
How do I get the data for a multivalued enumerated type out into a single cell within a WORD table? I htink it is getting the data but  not containing it to a single cell.

Thanks for any help with this

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Pierre Bentkowski (131●5●17) | answered Apr 24, 4:26 p.m.
edited Apr 24, 4:29 p.m.
Hello

The list of the selected values are return in their own XML element: <attribute:customAttribute ... />

Example, 3 values were selected for the Applicable Baseline attribute.
<rrm:attributes>
        <attribute:objectType attribute:itemId="OT_54fusP5EEe2mj7H4PMEmyg" attribute:name="Feature" attribute:projectAreaItemId="_14xw0P5EEe2mj7H4PMEmyg" attribute:projectAreaName="JKE Banking (Requirements Management)">
          <attribute:customAttribute attribute:datatype="http://www.w3.org/2001/XMLSchema#int" attribute:isEnumeration="true" attribute:isMultiValued="true" attribute:itemId="AD_5rPNQCofEe61PrRcm04QYA" attribute:literalId="AT_5ZPeUCofEe61PrRcm04QYA#_EO7wUyy6FDao7cdYuoRI7A"
            attribute:literalName="B2" attribute:name="Applicable Baseline" attribute:value="1" />
          <attribute:customAttribute attribute:datatype="http://www.w3.org/2001/XMLSchema#int" attribute:isEnumeration="true" attribute:isMultiValued="true" attribute:itemId="AD_5rPNQCofEe61PrRcm04QYA" attribute:literalId="AT_5ZPeUCofEe61PrRcm04QYA#_fCpoke6RIxTygHoo0WpH1w"
            attribute:literalName="B1" attribute:name="Applicable Baseline" attribute:value="0" />
          <attribute:customAttribute attribute:datatype="http://www.w3.org/2001/XMLSchema#int" attribute:isEnumeration="true" attribute:isMultiValued="true" attribute:itemId="AD_5rPNQCofEe61PrRcm04QYA" attribute:literalId="AT_5ZPeUCofEe61PrRcm04QYA#_EtWz5DsuHeactP8mSXHx1w"
            attribute:literalName="B3" attribute:name="Applicable Baseline" attribute:value="2" />
          <attribute:customAttribute attribute:datatype="http://www.w3.org/2001/XMLSchema#int" attribute:isMultiValued="false" attribute:itemId="identifier" attribute:name="Identifier" attribute:value="30909" attribute:valueTS="" />
          <attribute:customAttribute attribute:datatype="http://www.w3.org/2001/XMLSchema#int" attribute:isEnumeration="true" attribute:isMultiValued="false" attribute:itemId="AD_54UIgv5EEe2mj7H4PMEmyg" attribute:literalId="AT_54XL1P5EEe2mj7H4PMEmyg#_54Xy4P5EEe2mj7H4PMEmyg"
            attribute:literalName="Draft" attribute:name="Status" attribute:value="0" />
          <attribute:customAttribute attribute:datatype="http://www.w3.org/2001/XMLSchema#int" attribute:isEnumeration="true" attribute:isMultiValued="false" attribute:itemId="AD_54S6YP5EEe2mj7H4PMEmyg" attribute:literalId="AT_54ZoE_5EEe2mj7H4PMEmyg#_54aPIf5EEe2mj7H4PMEmyg"
            attribute:literalName="Medium" attribute:name="Stability" attribute:value="1" /></attribute:objectType>
      </rrm:attributes>

You should collect them and concatenate them into String variable and then print that string in the Cell.
When you query the attributes, sort them by attribute:name, and check for the following tags to determine what to do:
  • attribute:isEnumeration
  • attribute:isMultiValued


Regards

Pierre


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