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question asked: Nov 01 '18, 11:53 a.m.
question was seen: 1,350 times
last updated: Nov 07 '18, 1:34 p.m.

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Get file name using configuration file

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James G (11●6) | asked Nov 01 '18, 11:53 a.m.
edited Nov 01 '18, 12:15 p.m.

 Hi,

I am wondering if it is possible to access the name of the excel file in a configuration file. I see in the custom attributes section here - https://jazz.net/wiki/bin/view/Main/RQMExcelWordImporter - that there is a mention of using the excel document's properties:

"Along the same lines, you can access the properties of the spreadsheet that  you are working on. Examples:

requirement.dc:title=property(“Title”)

 requirement.dc:creator=property("Author")

requirement.jzalm:owner=property(“Company”) "

I tried doing this in my configuration file by doing this:

    testcase.category term=property(“Title”).value="validate"

 however, in the generated xml it just shows
    <category term=property("Title") value="validate"/>

So I am lead to believe that it either doesn't work or this doesn't do what I hoped it would. If it is possible to get the document's name, is it also possible to get the current tab's name?

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Mehul Patel (969●5) | answered Nov 02 '18, 2:41 a.m.
FORUM MODERATOR

James,


Getting current tab name is not possible, but it is possible to get the document name by using configuration syntax- 
            - property("full name") // full name with extension and path
            - property("name") // name with extension

Regards,
Mehul

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James G (11●6) | answered Nov 02 '18, 9:05 a.m.

 I tried using 

    testcase.category term=property(“name”).value="test"

It results in

<category term=property(“name”) value="test"/>

Is there something I'm missing here?

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Mehul Patel commented Nov 04 '18, 2:46 a.m.
FORUM MODERATOR

I did not get the last part of syntax - .value="test", could you please explain?

James G commented Nov 07 '18, 1:34 p.m. | edited Nov 07 '18, 1:34 p.m.

The .value="test" should just set the subcategory to "test". I'd like to try to set a category based on the file name and then a subcategory based on something in the sheet. That part works fine. I'm just struggling with getting the filename with property("name") or property("full name")

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