It's all about the answers!

Ask a question

Does RTC support WebSphere Cluster?


Daisy Huang (427) | asked Mar 29 '18, 4:36 a.m.
retagged Mar 30 '18, 3:45 p.m. by Ken Tessier (84117)

We're using RTC CCM for production systems. Does RTC support to be deployed to WebSphere Cluster? We're using WebSphere Application Server Network Deployment 8.9.9.10.


I tried googling and searching here, however so far no luck. If there's official document regarding the issue, please help point it out. 

Thanks in advance. 


Comments
Daisy Huang commented Mar 29 '18, 5:24 a.m. | edited Apr 01 '18, 8:22 p.m.

 From this link, https://www.ibm.com/support/knowledgecenter/SSYMRC_4.0.3/com.ibm.jazz.install.doc/topics/t_deploy_cluster_was_nd.html, I see that a "Clustering Feature Key File" is needed for deploying RTC on clustered WAS. Is this file contained in RTC 6.0.3 or higher version?

Accepted answer


permanent link
Ralph Schoon (55.5k23642) | answered Mar 29 '18, 5:29 a.m.
FORUM ADMINISTRATOR / FORUM MODERATOR / JAZZ DEVELOPER

This type of clustering is no longer supported and a new RTC clustering feature was introduced in RTC 6.0.4.

Geoffrey Clemm selected this answer as the correct answer

Comments
Daisy Huang commented Mar 29 '18, 5:51 a.m. | edited Apr 01 '18, 8:23 p.m.

 Hi Ralph,


Do you mean https://jazz.net/wiki/bin/view/Deployment/ChangeAndConfigurationManagementClusteredEnvironment this, so we use WAS Liberty since 6.0.4, right? 


Ralph Schoon commented Mar 29 '18, 7:14 a.m. | edited Apr 01 '18, 8:23 p.m.
FORUM ADMINISTRATOR / FORUM MODERATOR / JAZZ DEVELOPER

Daisy,

that is the new clustering and you can find it in the documentation and in the new and note worthy as well. It requires liberty profile.

2 other answers



permanent link
Donald Nong (14.3k213) | answered Mar 29 '18, 4:57 a.m.

You don't even mention the RTC version. But the simple answer is no.


permanent link
julius sahat (2511115) | answered Mar 30 '18, 6:09 a.m.

 Yes RTC support WAS ND for failover, not for load balancing

Your answer


Register or to post your answer.