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Dependant Enumerations


Ignacio Vazquez (111) | asked Apr 15 '14, 1:39 p.m.
edited Apr 16 '14, 4:59 a.m. by Ralph Schoon (63.1k33646)
Hi all,
Your help will be very much appreciated!!
Is there a special way to have two or more origin-dependant pairs of enumerations?


Regards
Ignacio Vazquez

user: ignaciov

Comments
sam detweiler commented Apr 15 '14, 2:01 p.m.

sorry, could you describe a little more what you want to do

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Lily Wang (4.9k714) | answered Apr 16 '14, 12:02 a.m.
This function is not supported by the Dependent Enumeration value set. However you can implement it using Script Based value set.
Please see the existing work item and workaround from https://jazz.net/jazz/web/projects/Rational%20Team%20Concert#action=com.ibm.team.workitem.viewWorkItem&id=139294

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