Dependant Enumerations
Ignacio Vazquez (1●1●1)
| asked Apr 15 '14, 1:39 p.m.
edited Apr 16 '14, 4:59 a.m. by Ralph Schoon (63.6k●3●36●46)
Hi all,
Your help will be very much appreciated!! Is there a special way to have two or more origin-dependant pairs of enumerations? Regards Ignacio Vazquez user: ignaciov |
One answer
This function is not supported by the Dependent Enumeration value set. However you can implement it using Script Based value set.
Please see the existing work item and workaround from https://jazz.net/jazz/web/projects/Rational%20Team%20Concert#action=com.ibm.team.workitem.viewWorkItem&id=139294 |
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Comments
sorry, could you describe a little more what you want to do