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Dependant Enumerations

Hi all,
Your help will be very much appreciated!!
Is there a special way to have two or more origin-dependant pairs of enumerations?


Regards
Ignacio Vazquez

user: ignaciov

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sorry, could you describe a little more what you want to do



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This function is not supported by the Dependent Enumeration value set. However you can implement it using Script Based value set.
Please see the existing work item and workaround from https://jazz.net/jazz/web/projects/Rational%20Team%20Concert#action=com.ibm.team.workitem.viewWorkItem&id=139294

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Question asked: Apr 15 '14, 1:39 p.m.

Question was seen: 3,763 times

Last updated: Apr 16 '14, 4:59 a.m.

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