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How can we get GC URL information from linked DNG artifact in RTC by using RPE?

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Reddeiah Reddy Mukka
(11●5●4●6) Jun 27 '22, 5:19 a.m.
Hello Team,

I am trying to implement a RPE template which will extract the link information from RTC for the artifacts which are linked in DNG GC Context.

Now i am able to extract the DNG artifact link URL which is of local DNG stream. My requirement is to extract the full link information along with GC Context.

How can i achieve that please guide?

Thanks,
Reddeiah Reddy Mukka

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Ian Barnard
FORUM ADMINISTRATOR / FORUM MODERATOR / JAZZ DEVELOPER Jun 28 '22, 9:20 a.m.
As a RM local stream can contribute to any number of (non-overlapping) GC streams, this doesn't seem likely to be easy unless you rigidly apply a constraint that an RM stream can only be in one GC stream. Then you'd have to access the GC APIs and search the results for the RM contribution - see the GC api docs https:jazz.net/gc/doc/scenarios - but that's a major constraint that you'll have to ensure isn't going to cause you problems

Reddeiah Reddy Mukka
Jun 29 '22, 4:05 a.m.
I want to get it from RPE not from GC API's. Is there any possible way to extract the data of GC URL from RTC by using RPE

Ian Barnard
FORUM ADMINISTRATOR / FORUM MODERATOR / JAZZ DEVELOPER Aug 23 '22, 4:50 a.m.
> DNG artifact link URL which is of local DNG stream This seems odd, if anything I would expect a GC configuration - what sort of link (Implements, Tracks Requirement, etc.) have you created from the work item? Also what version+ifix are you using? 

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Subramanya Prasad Pilar
(4.6k●1●6) Aug 22 '22, 2:07 p.m.

If RM stream is only in one GC stream, you can create a JavaScript array containing GC URL along with the contributors. This can be either hardcoded in RPE template or you can make data request on GC URL first and get the streams. When you are getting DNG local URL, you should be able to get the corresponding GC stream from the array.

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Question asked: Jun 27 '22, 5:19 a.m.

Question was seen: 4,596 times

Last updated: Aug 23 '22, 4:50 a.m.

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