Fetch the modules of all the component of a project area DNG
Hi All,
Actually i am able to fetch the module of a single component but when coming to fetch all the modules of all the components, then i am facing issue. Please let me know the solution for this.
Thanks in advance :)
I'll be looking forward for help.
Minakshi Verma
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Accepted answer
Ian Barnard (1.9k●6●13)
| answered Sep 20 '21, 12:02 p.m.
FORUM ADMINISTRATOR / FORUM MODERATOR / JAZZ DEVELOPER edited Sep 20 '21, 12:11 p.m.
Hi Minakshi
Using OSLC Query:
For modules in a single component you would use the local configuration and an OSLC query like oslc.where=rdm_types:ArtifactFormat=jazz_rm:Module or whatever way you want to locate the modules you're interested in.
Assuming there are multiple components in a project which contribute to a GC configuration, you can use that GC configuration URL as the configuration and the same OSLC query as for a single component will return all modules in components in the project you're querying where those components contribute to the GC configuration. BUT this won't/can't give you modules in components that don't contribute to the GC. And this won't/can't give you modules in other projects.
For components which don't contribute to a common GC you'll have to find each component and query it as for a single component.
If you want all modules across more than one project you'll have to query each project/component.
Using Reportable REST API https://jazz.net/wiki/bin/view/Main/DNGReportableRestAPI
The DNG Reportable REST API gives you another way to retrieve information from DNG.
A query like:
* https://SERVER:PORT/rm/publish/modules/*?projectURI=_NDNJ0NcLEeqXpuBdEolY7w&oslc_config.context=https://SERVER:PORT/rm/cm/stream/_XYZ where you replace the projectURI value with your project's UUID and the configuration URI with your configuration
will return XML about all modules in that configuration - you'll have to post-process to filter out modules you aren't interested in.
Once nice thing about reportable REST is you can paste the URL into a logged-in browser and see the results :-)
HTH
Ian
Minakshi Verma selected this answer as the correct answer
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