Show mutation status for files in a comparison of snapshots.
![]()
I want to get a list of all the changesets, and their file mutation status.
The closest thing i've come to is this cli command: ./lscm compare -I dcbsfw -r rtc snapshot "V2.01" snapshot "V1.3"which gives me this: Outgoing Changes Component (1043) "AppB" (1054) Sofus Albertsen <sofus.albertsen@some.dk> V1.1 2013/03/23 /AppB/src/dk /AppB/src/dk/df /AppB/src/dk/df/appB /AppB/src/dk/df/appB/AppB.java (1055) Sofus Albertsen <sofus.albertsen@some.dk> added new files 2013/04/23 /AppB/src/dk/df/appB/AppB2.java /AppB/src/dk/df/appB/AppB3.java (1056) Sofus Albertsen <sofus.albertsen@some.dk> 436: wi20 - WI20 2013/04/23 /AppB/src/dk/df/appB/AppB.java The problem here is that i cannot see what has happened to the files in a changeset like deleted, modified, created etc. How can i do that? I don't need to see what has happened with the file, but just like this: comparison of 2 snapshots in web Regards Sofus Albertsen |
Accepted answer
![]()
Shashikant Padur (4.2k●2●7)
| answered Apr 28 '13, 11:22 p.m.
JAZZ DEVELOPER edited Apr 28 '13, 11:23 p.m.
This is currently not possible with the compare command and there is a workitem open to address this issue. https://jazz.net/jazz/resource/itemName/com.ibm.team.workitem.WorkItem/180926
As a workaround, you could list the changes of the changeset using the "list changes" command which displays the status of each change.
Sofus Albertsen selected this answer as the correct answer
Comments I can see that the WI is triaged, and there are others wanting the same functionality, so hopefully it'll get implemented.
|