How to get the itemUUID and IVersionableHandle object of the particular (XML)file

0	Boopathy Nagaraj (15●1●7) \| asked Jul 26 '16, 5:36 a.m. edited Jul 26 '16, 12:10 p.m. by David Lafreniere (4.8k●7) Hello Jazz team How to retrieve the itemUUID of the particular(XML) file? Using that itemUUID how to get IversionableHandle object for that particular(XML) file?

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David Lafreniere (4.8k●7) | answered Jul 26 '16, 12:16 p.m.
FORUM MODERATOR / JAZZ DEVELOPER

If you have the workspace loaded, and want to find a particular file (by path) you can use ISharingManager#findShareable(). This returns an IShareable, and you can use IShareable#getVersionable() to get the IVersionableHandle (if the file is actually a shared file). Also #getItemId() on the versionable would return the item UUID.

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Boopathy Nagaraj commented Aug 03 '16, 4:41 a.m. | edited Aug 03 '16, 6:41 a.m.

Hello Mr.David

Can you provide me one simple example to get Ishareable object using ISharingManager#findShareable().

David Lafreniere commented Aug 05 '16, 3:22 p.m. | edited Aug 05 '16, 3:22 p.m.

FORUM MODERATOR / JAZZ DEVELOPER

This was not tested, but it should be something like:

IShareable shareable = FileSystemCore.getSharingManager().findShareable(new PathLocation("C:/someDir/someDir2/fileA.xml"), ResourceType.FILE);

IVersionableHandle fileHandle = shareable.getVersionable(progress); // Note: 'progress' here is an IProgressMonitor. This method should be run on a background thread and be passed in a progress monitor.

UUID fileUUID = item.getItemId();

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How to get the itemUUID and IVersionableHandle object of the particular (XML)file

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