Is it possible to replace symbol characters in dxl?

I am exporting objects from DOORS into a tex file. Things work fine, however, any special symbols like arrows, #, or degree symbols do not export. Since I am making this for LaTeX, I need the symbols to translate into syntax like \rightarrow for a symbol like -> or \greaterthan for >. Is this possible with regular expressions?
mirlo - Thu Mar 04 16:58:19 EST 2010

Re: Is it possible to replace symbol characters in dxl?
Mathias Mamsch - Fri Mar 05 02:02:10 EST 2010

Checkout the search function of the forum. I remember reading at least one code example for a replace. Regards, Mathias

Re: Is it possible to replace symbol characters in dxl?
mirlo - Fri Mar 05 14:56:40 EST 2010

I couldn't find the posting referred. I somewhat got the results I wanted however, I'm basically building a new string buffer, looping through the Object Text and applying a pattern match. On each successive loop, I shorten the string with a range of i:string length. Perhaps there is a better way, I'll have to try it out later when i get to the office. Basically, all I am trying to do is get the following effect, given the following string:

"the temperature is 15º"

I want to replace the degrees symbol with something like:

\degrees

so in my resulting text file I would have:

the temperature is 15\degrees

Re: Is it possible to replace symbol characters in dxl?
llandale - Sun Mar 07 14:33:46 EST 2010

Regular expressions and matching strings is very ineffecient. Here's my replace character function:

Buffer gl_fReplace_ToStngBuff = create(1024) // allows quick Combine

    

     //***********************

     void fReplaceChar(Buffer &InBuffer, char FromChar, string ToString)

     { // Change all occurrences of "FromChar" to "ToString" in the input Buffer.

     // If ToString is null then FromChar is deleted instead of replaced.

     // print "...fReplaceChar(Buffer)...\n"

     if (fIsEmptyBuf(InBuffer) or

     null FromChar or

     FromChar "" == ToString)

     return() // Nothing to do, Don't change anything

    

     int iPrev, iCurr, Count, LenIn

     bool Done

     Buffer bufReplace = create()

    

     gl_fReplace_ToStngBuff = ""

     gl_fReplace_ToStngBuff += ToString // Combining Buffers is more efficient than appending Strings.

     LenIn = length(InBuffer)

     Count = 0

     Done = false

     iCurr = -1

     iPrev = -1

     bufReplace = ""

     while (!Done)

     { iCurr = contains(InBuffer, FromChar, iPrev+1)

     if (iCurr == -1 or iCurr >= LenIn)

     { // Not found (or out-of-bounds??)

     Done = true

     combine(bufReplace, InBuffer, iPrev+1) // Add rest of InBuffer to bufReplace

     }

     else

     { // Found:

     combine(bufReplace, InBuffer, iPrev+1, iCurr-1) // Add portion before it was found

     combine(bufReplace, gl_fReplace_ToStngBuff, 0) // Insert ToString

     iPrev = iCurr // Update Pointer

     Count++

     }

     } // end while looking for the InChar

    

     // print "**fReplaceChar; InBuffer = " InBuffer "\n"

     // print "**fReplaceChar; changed; TempBuff = " Count " " tempStringOf(bufReplace) "\n"

     delete(InBuffer)

     InBuffer = bufReplace // Make Alias.

     return()

     } // end fReplaceChar(Buffer)

I think you can change 'degrees' as follows: fReplaceChar(bufText, charOf(160), "\\degrees")

Louie

Re: Is it possible to replace symbol characters in dxl?
mirlo - Sun Mar 21 10:53:38 EDT 2010

That function works great, thanks, I can now replace characters just fine.

Re: Is it possible to replace symbol characters in dxl?
witthoft_carl - Mon Sep 26 15:41:46 EDT 2016

llandale - Sun Mar 07 14:33:46 EST 2010
Regular expressions and matching strings is very ineffecient. Here's my replace character function:
Buffer gl_fReplace_ToStngBuff = create(1024) // allows quick Combine //*********************** void fReplaceChar(Buffer &InBuffer, char FromChar, string ToString) { // Change all occurrences of "FromChar" to "ToString" in the input Buffer. // If ToString is null then FromChar is deleted instead of replaced. // print "...fReplaceChar(Buffer)...\n" if (fIsEmptyBuf(InBuffer) or null FromChar or FromChar "" == ToString) return() // Nothing to do, Don't change anything int iPrev, iCurr, Count, LenIn bool Done Buffer bufReplace = create() gl_fReplace_ToStngBuff = "" gl_fReplace_ToStngBuff += ToString // Combining Buffers is more efficient than appending Strings. LenIn = length(InBuffer) Count = 0 Done = false iCurr = -1 iPrev = -1 bufReplace = "" while (!Done) { iCurr = contains(InBuffer, FromChar, iPrev+1) if (iCurr == -1 or iCurr >= LenIn) { // Not found (or out-of-bounds??) Done = true combine(bufReplace, InBuffer, iPrev+1) // Add rest of InBuffer to bufReplace } else { // Found: combine(bufReplace, InBuffer, iPrev+1, iCurr-1) // Add portion before it was found combine(bufReplace, gl_fReplace_ToStngBuff, 0) // Insert ToString iPrev = iCurr // Update Pointer Count++ } } // end while looking for the InChar // print "**fReplaceChar; InBuffer = " InBuffer "\n" // print "**fReplaceChar; changed; TempBuff = " Count " " tempStringOf(bufReplace) "\n" delete(InBuffer) InBuffer = bufReplace // Make Alias. return() } // end fReplaceChar(Buffer)
I think you can change 'degrees' as follows: fReplaceChar(bufText, charOf(160), "\\degrees")

Louie

The unicode for the degree sign is decimal 176 . decimal 160 so far as I can tell is a nonbreaking space.