Count entries in Multi-value ennumeration

I want to create a DXL attribute which looks at another attribute for each object (a multi ennumeration attribute), and counts how many ennumerations have been selected.

Is there a simple way to count the selected number of ennumerations in a multi ennumeration attributeand/or a normal ennumeration (i.e. return 1 or 0).

Seems like there should be but i can't find anything about this in the manual.
liamc - Mon Nov 29 11:11:48 EST 2010

Re: Count entries in Multi-value ennumeration
llandale - Mon Nov 29 11:32:08 EST 2010

You could retrieve the value and count the EOLs; I think single-enums have no EOL in which case the value is either null or not-null; and I think Multi always have an EOL even if only one is selected; you'll need to play with it. You an use the Buffer 'contains(Buf, char, offset) command in a loop, where 'char' is '\n' and offset is the previous results of contains, something like this:

Buffer buf = probeAttr_(obj, "MyMultiEnumAttr")
int Count = 0, Offset = -1,
    DebugCountLoops = 0
while (true)
{  Offset = contains(buf, '\n', Offset)  // ? I don't think you need "Offset+1" here?
   if (Offset >= 0) //
   then Count++
   else break
 
   if (DebugCountLoops++ > 20)
   {  print "Debug break " Count "\t" Offset "\n"
      break
   }
}
delete(buf)
print "# EOLs = Count "\n"

Got the debug statements in there for you lesser folks, not that I have EVER ever ever ever had to abort DOORS due to an invinite loop. :)

You could also read the value into a string and then loop through the length(Value) looking for '\n'; now that I think of it that would be faster since creating/deleting Buffers is VERY slow.

string Value = probeAttr_(obj, "MyMultiEnumAttr")
int i, Count = 0
for (i=0; i<length(Value); i++)
{  if (Value[i] == '\n') Count++
}
print "# EOLs = Count "\n"

You will need to try this out, but the following may prove to be correct:

int NumSelectedValues
if (null Value)
then NumSelectedValues = 0
else NumSelectedValues = CountEOLS+1

You could also retrieve the list of enums and then query the object specifically for whether the enum 'isMember'. Its a little tricky getting the attr type and its valid enums, so I'd go with the EOL method.

• Louie

Re: Count entries in Multi-value ennumeration
liamc - Mon Nov 29 11:48:26 EST 2010

Awesome llandale, you're a genius! I'd have never known to look for EOL.

this seems to work:
 

string Value = probeAttr_(obj, "MultiAtt")
int i, Count = 0
for (i=0; i<length(Value); i++)
{  if (Value[i] == '\n') Count++
}
//print "# EOLs = " Count "\n"
    obj.attrDXLName =  count ""

However, it seems to be off by 1 every time. Can't quite figure out why, hmmm

Re: Count entries in Multi-value ennumeration
liamc - Mon Nov 29 11:55:57 EST 2010

string Value = probeAttr_(obj, "MultiAtt")
int i, Count = 0
for (i=0; i<length(Value); i++)
{  if (Value[i] == '\n') Count++
}
//print "# EOLs = " Count "\n"
    obj.attrDXLName =  count ""

Re: Count entries in Multi-value ennumeration
liamc - Mon Nov 29 12:02:15 EST 2010

Re: Count entries in Multi-value ennumeration
liamc - Mon Nov 29 12:43:06 EST 2010

Bazinga

string Value = probeAttr_(obj, "MultiAttribute")
if(Value!=null){
int i, Count = 1
for (i=1; i<length(Value); i++)
{  if (Value[i] == '\n') Count++
}
obj.attrDXLName =  Count
}

Re: Count entries in Multi-value ennumeration
llandale - Mon Nov 29 18:58:03 EST 2010

string Value = probeAttr_(obj, "MultiAttribute")
if(Value!=null){
int i, Count = 1
for (i=1; i<length(Value); i++)
{  if (Value[i] == '\n') Count++
}
obj.attrDXLName =  Count
}

• Louie