show partial string from another attribute

llandale - Sat Mar 16 13:45:11 EDT 2013
This:

• string s = "12345678"
  • print s0:2 "\t" s3:6 "\n"

• 123 4567

• val += tempStringOf temp

• val += (tempStringOf temp)0:2

• obj.attrDXLName = probeAttr_(o, "Verification IDs")0:2

btela2000 - Mon Mar 18 13:52:12 EDT 2013
Hey Louie,

I truly appreciate the fast response! thank you! I just tried your code correction here:

/ DXL generated on 15 March 2013 by Attribute DXL wizard, Version 1.0

// The wizard will use the following comments on subsequent runs
// to determine the selected options and attributes. It will not
// take account of any manual changes in the body of the DXL code.

// begin parameters (do not edit)
// One attribute/property per line: true
// Show attribute/property names: false
// Include OLE objects in text: false
// Attribute: Verification IDs
// end parameters (do not edit)

Module m
AttrDef ad
AttrType at
m = module obj
ad = find(m,attrDXLName)
if(!null ad && ad.object)
{
at = ad.type
if(at.type == attrText)
{
string s
Buffer val = create
Buffer temp = create
ad = find(m,"Verification IDs")
if(!null ad)
{
probeRichAttr_(obj,"Verification IDs", temp, false)
val += (tempStringOf temp)0:2
}
obj.attrDXLName = richText (tempStringOf val)
delete val
delete temp
}
}
------------------------------I get the following errors:
-E- DXL: <Line:31> incorrectly concatenated tokens
-E- DXL: <Line:31> syntax error
-I- DXL: All done. Errors reported: 2. Warnings reported: 0.
I also tried to run your simple script and I couldnt't do that either. defintely a novice. maybe its how i put it it. I just tried your simple:
•string s = "12345678"
◦print s0:2 "\t" s3:6 "\n"
here's what I put into the dxl window:
string s = "12345678"
print s0:2 "\t" s3:6 "\n"
got these errors:
-E- DXL: <Line:2> incorrect arguments for function (print)
-E- DXL: <Line:2> undeclared variable (s0)
-E- DXL: <Line:2> syntax error
-I- DXL: All done. Errors reported: 3. Warnings reported: 0.

sorry if im not getting the simpler things right now. thank you, John

llandale - Mon Mar 18 16:10:05 EDT 2013
My bad, I forgot to preview the message before I posted. On the forums, something surrounded with backets [ and ] is interpreted as a URL. So typing "a[0:2]" looks like "a0:2". Solution is to escape the first or both with a backslash, typed like this: "a:\[0:2\]" it looks like "a[0:2]"

• string s = "12345678"
• print s[0:2] "\t" s[3:6] "\n"

btela2000 - Mon Mar 18 18:56:08 EDT 2013
Hey Louie,

thanks for the clarification. I was able to get the code to have no syntax errors, but then I got the popular "Attribute DXL Failed." It stated that it failed because it was not in rich text format. i suspect its choking on teh fact that Verification IDs (teh attribute it is analyzing) is not in rich text.
here's the error:
-R-E- DXL: <Line:33> String is not in rich text format
-I- DXL: execution halted

So tried to scrap that entire code and put in this line per your suggestion:

\\\\\\\\\
Module m
obj.attrDXLName = probeAttr_(obj, "Verification IDs")0:2
\\\\\\\\\\
I did confirm that it does work when I dont have the "0:2" in it.

thanks, John

btela2000 - Mon Mar 18 18:56:08 EDT 2013
Hey Louie,

thanks for the clarification. I was able to get the code to have no syntax errors, but then I got the popular "Attribute DXL Failed." It stated that it failed because it was not in rich text format. i suspect its choking on teh fact that Verification IDs (teh attribute it is analyzing) is not in rich text.
here's the error:
-R-E- DXL: <Line:33> String is not in rich text format
-I- DXL: execution halted

So tried to scrap that entire code and put in this line per your suggestion:

\\\\\\\\\
Module m
obj.attrDXLName = probeAttr_(obj, "Verification IDs")0:2
\\\\\\\\\\
I did confirm that it does work when I dont have the "0:2" in it.

thanks, John

btela2000 - Mon Mar 18 21:49:15 EDT 2013
I took another crack at it and it works! Thank you!

here's the code:

obj.attrDXLName = (probeAttr_(obj, "Verification IDs"))0:2